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100=45.522x-2.529x^2
We move all terms to the left:
100-(45.522x-2.529x^2)=0
We get rid of parentheses
2.529x^2-45.522x+100=0
a = 2.529; b = -45.522; c = +100;
Δ = b2-4ac
Δ = -45.5222-4·2.529·100
Δ = 1060.652484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45.522)-\sqrt{1060.652484}}{2*2.529}=\frac{45.522-\sqrt{1060.652484}}{5.058} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45.522)+\sqrt{1060.652484}}{2*2.529}=\frac{45.522+\sqrt{1060.652484}}{5.058} $
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